What is the final value of the variable var in the code snippet? public static void main(String[] args) { int var = 30; var = var + 2 / var; var++; }

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Prepare for the Arizona State University CSE110 Exam 1. Study with flashcards and multiple choice questions, each question has hints and explanations. Get ready for success!

To understand why the final value of the variable var is 31, let's break down the code snippet step by step.

Initially, var is set to 30. The next line, var = var + 2 / var;, involves two operations: addition and division.

First, let's address the division operation: 2 / var. Since var is currently 30, this expression evaluates to 2 / 30. In integer division (which is applied here because var is of type int), 2 divided by 30 yields 0, since the result is rounded down to the nearest whole number.

Now, substituting back into the equation:

var = var + 2 / var becomes var = 30 + 0, which results in var still being 30.

Next, we move to the next line of code: var++;. This statement increments var by 1. Since var was 30 just before this line, this increment changes its value to 31.

Thus, after executing both lines of code, the final value of var is indeed 31. This detail illustrates how integer division works

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