What will be the value of x and y after the assignments int x = 20; int y = 10; x = (x - y) * 2; y = x / 2;?

To understand the values of x and y after the assignments, let's break down the operations step-by-step, starting with the initial values of x and y.

Initially, x is assigned the value of 20, and y is assigned the value of 10.

Next, the first assignment modifies x using the expression (x - y) * 2. Here's the breakdown:

1. First, we calculate x - y, which is 20 - 10 = 10.
2. Then, we multiply the result by 2: 10 * 2 = 20.
3. After this operation, x is updated to 20.

Now we look at the next assignment, where y is computed using the expression x / 2:

1. Since the new value of x is still 20, we calculate x / 2, which is 20 / 2 = 10.
2. Thus, y is updated to 10.

After performing these operations, we find that x remains 20 and y is also 10. Therefore, the final values after all assignments are x = 20 and y = 10. This reflects the initial values of both variables before any modifications, confirming that the